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2(a^2-2)+3a-4=0
We add all the numbers together, and all the variables
3a+2(a^2-2)-4=0
We multiply parentheses
2a^2+3a-4-4=0
We add all the numbers together, and all the variables
2a^2+3a-8=0
a = 2; b = 3; c = -8;
Δ = b2-4ac
Δ = 32-4·2·(-8)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{73}}{2*2}=\frac{-3-\sqrt{73}}{4} $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{73}}{2*2}=\frac{-3+\sqrt{73}}{4} $
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